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习题3.2

  1. 假设函数 P(x)P(x)Q(x)Q(x) 于区间 [α,β][\alpha,\beta] 上连续,y=φ(x,x0,y0)y = \varphi(x,x_0,y_0) 是方程 dydx=P(x)y+Q(x)\frac{\mathrm{d}y}{\mathrm{d}x} = P(x)y + Q(x) 的解,y0=φ(x0,x0,y0)y_0 = \varphi(x_0,x_0,y_0),试求 φx0,φy0\frac{\partial \varphi}{\partial x_0},\frac{\partial \varphi}{\partial y_0}φx\frac{\partial \varphi}{\partial x}.

  2. 给定方程 dydx=sinyx\frac{\mathrm{d}y}{\mathrm{d}x} = \sin \frac{y}{x},试求 y(x,x0,y0)x0\frac{\partial y(x,x_0,y_0)}{\partial x_0}y(x,x0,y0)y0\frac{\partial y(x,x_0,y_0)}{\partial y_0}x0=1,y0=0x_0 = 1,y_0 = 0 时的表达式.

习题4.1

  1. 证明非齐次线性微分方程的叠加原理:设 x1(t),x2(t)x_1(t),x_2(t) 分别是非齐次线性微分方程

dnxdtn+a1(t)dn1xdtn1++an(t)x=f1(t),\frac{\mathrm{d}^n x}{\mathrm{d}t^n} + a_1(t)\frac{\mathrm{d}^{n-1}x}{\mathrm{d}t^{n-1}} + \cdots + a_n(t)x = f_1(t),

dnxdtn+a1(t)dn1xdtn1++an(t)x=f2(t)\frac{\mathrm{d}^n x}{\mathrm{d}t^n} + a_1(t)\frac{\mathrm{d}^{n-1}x}{\mathrm{d}t^{n-1}} + \cdots + a_n(t)x = f_2(t)

的解,则 x1(t)+x2(t)x_1(t) + x_2(t) 是方程

dnxdtn+a1(t)dn1xdtn1++an(t)x=f1(t)+f2(t)\frac{\mathrm{d}^n x}{\mathrm{d}t^n} + a_1(t)\frac{\mathrm{d}^{n-1}x}{\mathrm{d}t^{n-1}} + \cdots + a_n(t)x = f_1(t) + f_2(t)

的解.

  1. 已知齐次线性微分方程的基本解组 x1,x2x_1,x_2,求下列方程对应的非齐次线性微分方程的通解: (1) xx=cost, x1=et, x2=etx'' - x = \cos t, \ x_1 = \mathrm{e}^t, \ x_2 = \mathrm{e}^{-t}; (3) x+4x=tsin2t, x1=cos2t, x2=sin2tx'' + 4x = t\sin 2t, \ x_1 = \cos 2t, \ x_2 = \sin 2t; (5) t2xtx+x=6t+34t2, x1=t, x2=tlntt^2 x'' - tx' + x = 6t + 34t^2, \ x_1 = t, \ x_2 = t\ln t;

  2. 已知方程 d2xdt2x=0\frac{\mathrm{d}^2 x}{\mathrm{d}t^2} - x = 0 有基本解组 et,et\mathrm{e}^t,\mathrm{e}^{-t},试求此方程适合初值条件 x(0)=1, x(0)=0x(0) = 1, \ x'(0) = 0x(0)=0, x(0)=1x(0) = 0, \ x'(0) = 1 的基本解组(称为标准基本解组,即有 W(0)=1W(0) = 1),并由此求出方程适合初值条件 x(0)=x0, x(0)=x0x(0) = x_0, \ x'(0) = x'_0 的解.

  3. xi(t) (i=1,2,,n)x_i(t) \ (i = 1,2,\cdots,n) 是齐次线性微分方程 (4.2) 的任意 nn 个解,它们所构成的朗斯基行列式记为 W(t)W(t). 试证明 W(t)W(t) 满足一阶线性微分方程

W+a1(t)W=0,W' + a_1(t)W = 0,

因而有

W(t)=W(t0)et0ta1(s)dst0, t(a,b).W(t) = W(t_0)\mathrm{e}^{-\int_{t_0}^t a_1(s)\mathrm{d}s}t_0, \ t \in (a,b).

  1. 试证 nn 阶非齐次线性微分方程 (4.1) 存在且最多存在 n+1n+1 个线性无关解.
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